2/3x^2+20=2

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Solution for 2/3x^2+20=2 equation: 



2/3x^2+20=2

We move all terms to the left:

2/3x^2+20-(2)=0



Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

2/3x^2+18=0

We multiply all the terms by the denominator


18*3x^2+2=0

Wy multiply elements

54x^2+2=0

a = 54; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·54·2
Δ = -432
Delta is less than zero, so there is no solution for the equation

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